Accounting for Pressure Drop in Propeller Calculations

AI Thread Summary
The discussion focuses on optimizing a system with propellers or fans driving air through a packed bed for scrubbing, emphasizing the need to account for pressure drop in the slipstream. The user has established calculations using blade element theory but realizes it does not factor in this pressure drop. They explore using Bernoulli's equation to determine the pressure differential and consider how to incorporate this into their calculations for flow rates and speeds. Ultimately, they conclude that subtracting the pressure drop multiplied by the disc area from the force calculated via blade element theory is a viable approach. The user resolves their query, indicating they have found a solution.
KarenRei
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I'm trying to optimize a system involving one or more propellers / fans driving air through a packed bed for scrubbing (compressed then expanded) and out the other side to achieve propulsive thrust. So there's going to be a pressure drop in the slipstream. I've already set up a system to do the calculations for a single propeller via blade element theory, to figure out how much shaft power equals how much flow rate at what speeds and so forth. However, it has no accounting for a pressure drop in the slipstream.

How does one work a pressure drop behind the propeller into prop calculations? I'm sure there's some set of formulae for accounting for such a situation.

Here's what I've been using so far for prop calculations: ewp.rpi.edu/hartford/~ernesto/F2012/EP/MaterialsforStudents/‌

If I plug in Bernouli's equation into the output (0.5 * rho * (Vinf^2 - Vslip)) I get a couple hundred Newtons pressure differential** But I need to reverse that, to work the pressure drop into calculating flow rates / speeds / etc. Hmm...

Ed: *** Seems unusually small. Multiplied by the disc area it comes out with far lower of a force than blade element theory calculates... Hmm... perhaps I just subtract from the force (pressure drop * disc area), since pressure is force over area? Surely that's right. Maybe I need to double check my Bernouli's formula...

Sorry, ended up sort of thinking out loud here. I'm pretty sure that's right, you can delete this.
 
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KarenRei said:
Sorry, ended up sort of thinking out loud here. I'm pretty sure that's right, you can delete this.
Problem solved.
 
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