Action/reaction on superposed masses

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When two masses are stacked, the total force exerted on the system equals their combined weight, which is supported by the hand. The reaction force from the top mass (mass 2) is transmitted through the bottom mass (mass 1) to the hand, rather than acting directly on it. Mass 1 supports mass 2 by exerting a force equal to its weight, preventing mass 2 from falling. The hand must provide the necessary reaction force to support both masses; without this, they would fall. The interactions between the masses and the hand illustrate the principles of action and reaction in physics.
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If two masses are superposed one on the other and my hand is holding supporting them, the force that is applied on the system is equivalent to their weight. So the reaction of those two masses toward my hand is also equivalent to their combined weight. If mass 1 is on my hand, and mass 2 on mass 1, mass 1 transfers an amount of force to mass 2, which is equivalent to its weight. By action reaction this weight also applies on mass 1. Why is it that the reaction of mass 2 is directly transferred to my hand trought mass 1 and not acting directly on it?
 
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Werg22 said:
.. Why is it that the reaction of mass 2 is directly transferred to my hand trought mass 1 and not acting directly on it?
It's not. The reaction is indirect.
Mass2 is directly suppported by mass1, which is directly supported by your hand.
Your hand must supply the reaction that supports both masses, otherwise they will fall to the ground. This reaction acts directly on mass1 since that is the object that your hand is in contact with.
Mass1 must then supply (directly) a reaction upon mass2, where it is in contact with it, and so prevent mass2 from falling through mass1 !
 
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