Actual rankine cycle - Work done by pump

AI Thread Summary
In an actual Rankine cycle, the work done by the pump can typically be neglected unless a high degree of accuracy is required for specific analyses. The work term associated with the pump is often insignificant when compared to the heat added by the boiler and the work output from the turbine. This is primarily because the pump is moving liquid condensate, which requires much less energy than compressing a gas or vapor. Therefore, in most practical scenarios, the pump's work does not significantly impact the overall thermal efficiency calculation. Neglecting the pump work simplifies the analysis without substantial loss of accuracy.
Jameseyboy
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Hi,

In what cases do I neglect the work done by the pump in an actual rankine cycle?

I am reading that h5-h4 is negligible but in what circumstances do I accept this.

Is this only for ideal rankine cycles?

As I understand thermal efficiency is (work out + work in)/Heat in

Thanks
 
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Unless you are doing a very specific analysis which requires a good degree of accuracy, you can almost always neglect the work done by the pump. If you are unsure why, I'd recommend that you calculate the work term and compare it to the heat added and rejected by the boiler and condenser, respectively, and the work out from the turbine. You will see notice that the work done by the pump is very insignificant compared to the other processes. The reason the work done by the pump is so small is because it is pumping liquid condensate as opposed to a gas (or vapour) which would require a compressor and a much larger energy input.
 
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