Add Resistors: Solve Circuit Value

  • Thread starter Thread starter magnifik
  • Start date Start date
  • Tags Tags
    Resistors
AI Thread Summary
The discussion focuses on solving a circuit problem involving resistors, specifically identifying which resistors are in series or parallel to simplify the circuit to a single equivalent resistor. The user struggles to determine the configuration of the resistors, particularly how the 3-ohm resistor interacts with the 2-ohm resistors. Clarification is provided that none of the resistors are in series with each other, and the user is encouraged to first identify parallel pairs before combining them. The goal is to arrive at a total resistance value of 2 ohms. Understanding the correct configuration of resistors is crucial for solving the problem effectively.
magnifik
Messages
350
Reaction score
0

Homework Statement



http://img8.imageshack.us/img8/4413/81107636.jpg

i'm a noob, and i am having trouble adding resistors. this circuit can be reduced to 1 resistor. what is its value?

Homework Equations


parallel: 1/Rtot=1/R1+1/R2+1/R3+1/R4
series: Rtot=R1+R2+R3+R4

The Attempt at a Solution


so i thought 3, 2, 2 added up in series and you just do 6/8+1/4, but this isn't right. =/ I'm having trouble discerning which resistors are parallel and which are in series. any help would be appreciated.
 
Last edited by a moderator:
Physics news on Phys.org
2 resistors R1 and R2 are in series if one connector of R1 is connected to a connector of R2 and nothing else is connected to these connectors. (or if you can determine that no current can flow through such a connection)

None of the resistors here is in series with any other.
The 3 ohm resistance isn't in series with any of the 2 ohm resistances because the point between the 3 ohm resistance and any of the 2 ohm resistances is also connected to the other 2 ohm resistance

2 resistors are parallels if one connector of R1 is connected to a connector of R2 and the other connector of R1 is connected to the other connector of R2. There's only 1 pair of
resistances here that's parallel.

The direction they are drawn in doesn't matter.

Once you combined those resistances, you can look again for a pair of resistances that is in series or parallel.
 
huh? so are you saying i can disregard the 3 Ohm resistor?
i know the answer is supposed to be 2. i don't know how to get there though.
 
magnifik said:
huh? so are you saying i can disregard the 3 Ohm resistor?
i know the answer is supposed to be 2. i don't know how to get there though.

No. I said the 3 ohm resitor isn't in series with any of the 2 ohm resistances. What you have to do is find the pair of resistances that's parallel, combine those and then look for other series of parallel pairs
 
is 3 parallel with 4 and 2 is parallel with 2?
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top