Adding a dielectric to capacitors

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Homework Help Overview

The discussion revolves around the effects of inserting a dielectric slab into one of two identical capacitors, specifically focusing on changes in potential difference, charge, capacitance, and potential energy. The subject area is primarily related to electrostatics and capacitor behavior in circuits.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of inserting a dielectric on the first capacitor, questioning whether it affects the potential difference and charge. There is discussion about how the dielectric influences the electric field and the resulting charge on the plates. The relationship between capacitance and potential energy is also examined.

Discussion Status

Some participants have provided guidance on reconsidering the effects of the dielectric on charge and potential energy. Multiple interpretations of the effects on charge and energy are being explored, indicating a productive direction in the discussion.

Contextual Notes

Participants are working within the constraints of a homework assignment that requires specific answers to statements regarding the behavior of capacitors with and without dielectrics. There is an ongoing examination of assumptions related to voltage and charge in parallel circuits.

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Homework Statement



Fig. 1 and 2 show a dielectric slab being inserted between the plates of one of two identical capacitors, capacitor 2. Select the correct answer to each of the statements below (enter I for `increases', D for `decreases', or S for `stays the same').

1. In Fig. 2, the potential difference between the plates of capacitor 1 _______ when the dielectric is inserted.
2. In Fig. 2, the charge on capacitor 2 _______ when the dielectric is inserted.
3. In Fig. 2, the capacitance of capacitor 1 _______ when the dielectric is inserted.
4. In Fig. 1, the potential energy stored in capacitor 2 _______ when the dielectric is inserted.

http://i.imagehost.org/view/0204/prob45

Homework Equations




The Attempt at a Solution



1. Stay the same - would it affect capacotor 1
2. stay the same, wouldn't the charge still be the sdame on the plates
3. stay the same - like 1
4. decrease - adding a dielectric decreases the potential, doesn't it
 
Last edited by a moderator:
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I agree that the first capacitor shouldn't change. Rethink your answers to the other two.
 
For 2, would the charge decrease because the electric field decreases (due to the dielectric).
and for 4,
would the potential increase, because the capitance would increase (C is proportional to K), and the energy is 0.5C(V)2
 
So from circuits you know that all the elements in parallel will always have the same voltage. Given that the voltage of the capacitor with the dielectric remains the same, what must happen to the charge?
 

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