mr_coffee said:Hello everyone, I'm confused on why I'm missing this problem. Here is my work and problem:
http://suprfile.com/src/1/25o5ux/lastscan.jpg
Any ideas?
I know you add up capitors in series like
(c1)(c2)/(c1+c2)
in parellel
c1 + c2 +...+cn
To add up capacitors in series, you simply add the values of the capacitors together. This means that the total capacitance will be the sum of each individual capacitor's capacitance. For example, if you have three capacitors with values of 2μF, 3μF, and 5μF, the total capacitance in series would be 10μF (2μF + 3μF + 5μF).
Yes, capacitors can also be added in parallel. In this case, the total capacitance will be the sum of the reciprocals of each individual capacitor's capacitance. This means that the total capacitance will be larger than the individual capacitance values. For example, if you have the same three capacitors from the previous question, the total capacitance in parallel would be 1/(1/2 + 1/3 + 1/5) = 30/11 ≈ 2.73μF.
There are different ways of calculating the total capacitance in a circuit, and some methods may yield slightly different results. It is also possible that there was a rounding error in the book's calculation. It is important to understand the principles behind adding capacitors in series and parallel, rather than focusing on getting an exact answer.
No, the voltage across each capacitor in a series/parallel circuit can be different. In a series circuit, the voltage is divided between each capacitor based on their individual capacitance values. In a parallel circuit, all capacitors have the same voltage, but the total voltage across the circuit may be different depending on the individual capacitance values.
Yes, you can mix capacitors with different values in a series/parallel circuit. However, it is important to note that the total capacitance will be affected by the values of the individual capacitors. It is best to use capacitors with similar values in a series/parallel circuit for more accurate results.