Archived Adiabatic expansion in a steady flow question

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The discussion revolves around a problem involving adiabatic expansion of a perfect gas, where the initial and final conditions are specified. The user calculates the work done during the expansion but arrives at a different answer than the textbook, prompting a request for assistance. Key equations related to adiabatic processes and specific heats are referenced, including the first law of thermodynamics and the relationship between specific heats. The user’s approach to calculating work done is acknowledged as correct, indicating a solid understanding of the principles involved. The thread emphasizes the importance of careful application of thermodynamic equations in solving such problems.
wilkie610
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I an working on a problem in the text "Mechanics and Thermodynamics of Propulsion" 2e. The problem states a perfect gas with molecular weight M=20 and a specific heat ratio of Y=1.2 expands adiabatically in steady flow from a pressure of 6MPa, a temperature of 3000K, and a velocity of 200 m/s to a final pressure of 0.101 MPa. If the final temperature is 1800K and the final velocity is negligible, what is the work done

I know that adiabatic means no heat in or out of the system so dq=0
Y=cp/cv and cp=cv+R
dq=de+dw

My attempt:
First i find R=8314.3/20=415.715
then i find cv by cv=R/(Y-1) cv=2078.58
thus dw= (-de) where de=cv(T2-T1)
my answer for the work done is 2494.29 kJ/kg however the books answer is 3013 Kj/kj

what am i doing wrong?
thanks for your help
 
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dw = m*[(e2-e1)+(p2/rho2 - p1/rho1)+(v2^2 / 2 - v1^2 / 2)]
so, v2 = 0 , p/rho = RT(p=rho*R*T)
and Cp=Cv+R finally dw = CP(T2-T1) - v1^2 / 2

you do not think V1 ok?
 
Junyong said:
dw = m*[(e2-e1)+(p2/rho2 - p1/rho1)+(v2^2 / 2 - v1^2 / 2)]
so, v2 = 0 , p/rho = RT(p=rho*R*T)
and Cp=Cv+R finally dw = CP(T2-T1) - v1^2 / 2

you do not think V1 ok?
This looks correct to me. Nice job of applying the open system version of the 1st law.
 
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