Air Puck Correct Method or not

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The discussion revolves around the physics of an air puck system involving a mass on a string. The tension in the string is calculated to be 9.8N, derived from the equilibrium of forces acting on the suspended mass. The horizontal force acting on the string is also identified as the tension, which remains at 9.8N. The speed of the puck is determined to be 6.3 m/s using centripetal force equations. Clarifications are sought regarding the reasoning for the centripetal forces and the requirement for an angle in determining the horizontal force.
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Air Puck ! Correct Method or not...

Homework Statement



An air puck of mass 0.25kg is tied to a string and allowed to revolve in a circle of radius 1.0m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table and a mass of 1kg is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves

a. What is the tension in the string ?
b. What is the horizontal force acting on the string ?
c. What is the speed of the puck ?

Homework Equations



\SigmaF = m * a
F_c = (m * v^2) / r
a_c = v^2 / r

The Attempt at a Solution



a.
\SigmaF_y = m * a = 0
T - mg = 0
T = mg = 1.0kg * 9.8m/s^2 = 9.8N

b.
F_c = Tension on th string = 9.8N

c.
F_c = (m * v^2) / r = 9.8N
(0.25kg * v^2) / 1.0m = 9.8N
v = \sqrt{39.2} = 6.3 m/s

Is this correct...THANKS!
 
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You seem to have it under control.
 
3a. is correct, but it has incorrect --as near as I can tell- reasoning. Just recall Newton's Third Law for centripetal forces. Also, for 3b. it asks what is the horizontal force is; which requires an angle for the center of the system; not certain on how you are supposed to acquire that answer.
 
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andrevdh said:
You seem to have it under control.

Thanks a lot !
 
very very helpful
 
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