Airplane propeller and plane's velocity relative to the ground.

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Homework Help Overview

The discussion revolves around an airplane propeller's rotational speed and the airplane's velocity relative to the ground. Participants are exploring how to calculate the speed of a point on the tip of the propeller from different reference frames, specifically from the pilot's perspective and from an observer on the ground.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss converting rotational speed from revolutions per minute to meters per second and the implications for calculating speed relative to different observers.
  • There is confusion regarding how to combine the velocities of the propeller tip and the airplane, particularly when considering their perpendicular relationship.
  • Some participants question the application of trigonometric relationships and the use of Pythagorean theorem for finding resultant velocities.

Discussion Status

The conversation has progressed with participants sharing their attempts and clarifying their understanding of the problem. There is acknowledgment of the need to use Pythagorean theorem to find the resultant velocity, indicating a productive direction in the discussion.

Contextual Notes

Participants note the challenge of relating the airplane's speed to the propeller's speed, particularly in the context of their perpendicular vectors. There is an emphasis on ensuring the correct application of equations and understanding the geometry of the situation.

rosstheboss23
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[SOLVED] Airplane propeller and plane's velocity relative to the ground.

Homework Statement


An airplane propeller rotates at 2200 rev/min while the airplane flies at a speed of 550 km/h relative to the ground. The plane's velocity is parallel to the propeller's axis of rotation.
Part a) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by the pilot?

Part b) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by an observer on the ground?

Homework Equations


v=w times r
v=w times r times sin delta



The Attempt at a Solution


I got part a asking speed relative to pilot by converting 2200rev/min to m/s, but part b has me stuck...I don't know if I am missing an equation that I could possibly use but I tried to convert the speed relative to ground to m/s and add it to the 345.57m/s I got as the answer for part a.
 
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rosstheboss23 said:

Homework Statement


An airplane propeller rotates at 2200 rev/min while the airplane flies at a speed of 550 km/h relative to the ground. The plane's velocity is parallel to the propeller's axis of rotation.
Part a) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by the pilot?

Part b) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by an observer on the ground?

Homework Equations


v=w times r
v=w times r times sin delta

The Attempt at a Solution


I got part a asking speed relative to pilot by converting 2200rev/min to m/s, but part b has me stuck...I don't know if I am missing an equation that I could possibly use but I tried to convert the speed relative to ground to m/s and add it to the 345.57m/s I got as the answer for part a.
Notice that the linear velocity of the propeller tip is perpendicular to the velocity of the plane.
 
Remembering that how would I relate 550km/hr to the speed seen by the pilot that is what has me confused. It should form a 90 degree angle and be the same as I calculated in a, but that doesn't work...I tried v= w times r times sin delta and it didn't work.
 
rosstheboss23 said:
Remembering that how would I relate 550km/hr to the speed seen by the pilot that is what has me confused. It should form a 90 degree angle and be the same as I calculated in a, but that doesn't work...I tried v= w times r times sin delta and it didn't work.
The speed is the magnitude of the resultant velocity. How do you normally find the magnitude of two perpendicular vectors?
 
Oh...now I understand this. I would use pythagorean's theorem to get the resultant velocity. Thanks I appreciate your help.
 
rosstheboss23 said:
Oh...now I understand this. I would use pythagorean's theorem to get the resultant velocity. Thanks I appreciate your help.
Correct! No problem :smile:
 

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