How Do You Calculate the Mass and Runway Distance for a Lufthansa A320?

  • Thread starter Thread starter Cole07
  • Start date Start date
  • Tags Tags
    Airplane Bullet
AI Thread Summary
To calculate the mass of a Lufthansa A320, the thrust from its two engines must be combined, resulting in a total force of 206 kN. Using the equation F = ma, the mass is determined to be approximately 70,558 kg. For calculating the runway distance before lift-off, the correct formula is D = Vit + 0.5at^2, which accounts for acceleration. The lift-off speed of 72.99 m/s achieved in 25 seconds results in a distance of about 912.375 meters. Proper attention to units and equations is crucial for accurate calculations.
Cole07
Messages
106
Reaction score
0

Homework Statement



A Lufthansa A320 accelerates from rest to lift-off speed of 72.99 m/s in 25.00 s. Each of the plane's two jet engines provides a forward force (thrust) of 103.00 kN. What is the mass of the plane?

How far does it travel down the runway before lift-off?

2. Governing equations
Vf=Vi+at
EF=ma
D=Vit+at^2

The Attempt at a Solution


Vf=72.99
Vi=0
a=?
t=25.00s
I used Vf=Vi+at to get a=2.9196
then EF=ma to solve for mass and got 35.27880532 which i was told was wrong i went back and looked at the problem and thought that since the plane has two engines i would double the mass, but it was still wrong. and i tried D=Vit+at^2 for the second problem, but it didn't work either i don't understand what I'm doing wrong. any help would be appreciated
 
Last edited:
Physics news on Phys.org
Cole07 said:

The Attempt at a Solution


Vf=72.99
Vi=0
a=?
t=25.00s
I used Vf=Vi+at to get a=2.9196
So far, so good. (Don't forget units.)
then EF=ma to solve for mass and got 35.27880532 which i was told was wrong i went back and looked at the problem and thought that since the plane has two engines i would double the mass, but it was still wrong.
F = ma is the right approach. But what's the total F? There are two engines, each giving their own force. And be careful with units: 1 kN = 1 kilo-N = 1000 N.
 
I think it should read like this:

103kN x 2 = 206kN
206kN = 206000 Newtons (N)

F=ma

206000 N = (m) (2.9196 m/s^2)

m = 206000 N / 2.9196 m/s^2
 
ok i got the mass of the plane to be 70557.61063kg, but i still don't know what I'm doing wrong to get the distance traveled down the runway.
 
d = (1/2)(vi + vf)(t)
 
i got it 912.375m thank you!
 
Cole07 said:
ok i got the mass of the plane to be 70557.61063kg, but i still don't know what I'm doing wrong to get the distance traveled down the runway.

You had a mistake in your distance equation:
D=Vit+at^2
That should be D = Vit + 0.5at^2.
 
Back
Top