Al68 said:
Sure, if we want to call the standard SR simultaneity convention arbitrary.
The standard SR simultaneity convention is only intended for inertial frames, while you are talking about a non-inertial observer who changes velocities. Keep in mind that while the simultaneity convention for inertial
frames is not arbitrary (it is physically 'natural' since the laws of physics will obey the same equations in all inertial frames constructed this way), it
is a matter of arbitrary linguistic convention to say that if I am an inertial observer, "my" frame is the inertial frame where I am at rest. It's not as though it's any easier to calculate things using the inertial frame where I am at rest than it is to calculate things using the frame where I am moving at 0.99c, it's purely an arbitrary convention to treat one of these as representing my "perspective" somehow (after all neither reflects what I actually
see visually). And for a non-inertial observer, not only is there no "natural" reason to say that their "perspective" at any given moment is represented by the inertial frame where they are instantaneously at rest, but this isn't even a standard accepted linguistic convention.
Al68 said:
In other words, the observer would use the standard SR convention to conclude it was year 2090 "now" on Earth and the standard SR convention to conclude it is year 2015 "now" on earth.
I disagree that any such convention exists for non-inertial observers. The convention about equating an observer's perspective on simultaneity with what is true in the inertial frame where they are at rest is usually taken to apply only to ideal inertial observers who move at constant velocity for all time (or at least for the entire window of time that a given word-problem is looking at), as far as I've seen.
Al68 said:
Is this not exactly how the twins paradox is analyzed in standard resolutions?
The most common resolution I've seen says nothing about switching inertial frames midway through the problem, it just notes that the traveling twin does not remain at rest in any inertial frame, so you can't calculate the elapsed time on the inertial twin's clock by using the standard time dilation which only works in inertial frames (and if you stick to anyone inertial frame, you see that for part of the journey the non-inertial twin must have been moving faster than the inertial one and thus aging slower during that phase). Some ways of answering the twin paradox do bring up the difference in simultaneity between the outbound rest frame and the inbound rest frame (which means that the time on the inertial twin's clock at the moment of the non-inertial twin's turnaround is very different in the two frames), but only to explain why you can't calculate how much the inertial twin ages by taking the sum of the the elapsed time on the inertial twin's clock from departure to turnaround in the outbound frame and then from turnaround to reunion in the inbound frame (which you could do if there was no disagreement in simultaneity between the two frames). The idea is usually
not to imply that you should actually use some kind of non-inertial frame where there is a sudden "jump" in the inertial twin's age at the moment of turnaround, at least not unless you want to get into the issue of
pseudo-gravitational fields and pseudo-gravitational time dilation in non-inertial frames.
Al68 said:
Does the fact that the ship twin is non-inertial invalidate the conclusion because there are other ways to represent the ship observer's perspective?
Invalidate what conclusion? If you want to you
can analyze things from the perspective of a non-inertial frame whose simultaneity convention agrees with that of the non-inertial twin's instantaneous inertial rest frame at every moment, but I still don't understand what this has to do with favoring Lorentzian relativity, or what you even mean by that if it's distinct from the Lorentz ether theory.