An ideal (lossless) transformer has 4 times as many turns

  • Thread starter Thread starter bckcookie
  • Start date Start date
  • Tags Tags
    Transformer
AI Thread Summary
An ideal transformer with four times as many turns on the primary winding as on the secondary is analyzed with a 10k ohm load and a 10V peak voltage source. The resistance presented to the voltage source can be calculated using the formula rin = (N1/N2)^2 x RL. The secondary voltage can be determined based on the primary voltage, leading to the calculation of the secondary current. Subsequently, the primary current can be found, and the input resistance can be derived from the primary voltage divided by the primary current. The discussion focuses on solving for these electrical parameters in the context of transformer operation.
bckcookie
Messages
17
Reaction score
0

Homework Statement


An ideal (lossless) transformer has 4 times as many turns on the primary winding as it has on the secondary winding. The secordary winding is loaded with a 10k ohm resistor and a sinusoidal voltage source having negligible resistance and a peak voltage of 10V is connected to the primary .

1. the value nearest to the resistance presented to the voltage source??
2. the value nearest to the peak current flowing in the secordary winding??


Homework Equations



Input resistance rin = e1/i1 = e2N1/N2 x n1/i2N2 = e2/i2{N1/N2}^2

rin = (N1/N2)^2 x RL

The Attempt at a Solution



I can't find out the solution 1. & 2., please advise!
 
Physics news on Phys.org


Hi bckcookie! If the primary voltage is 10Vpk, what is the secondary voltage?

Determine the secondary current with that load of 10kΩ on the secondary.

Determine the primary current.

What is the result of dividing primary voltage by primary current?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Current and Impedance in a Transformer
Replies
4
Views
4K
Physics - transformer / resistance question
Replies
4
Views
5K
Effective resistance of secondary circuit in transformers
Replies
2
Views
6K
Engineering Therefore, R's=0.057/26.5^2=0.000078 Ω2% of 415 V is 8.3 V
Replies
1
Views
2K
Current and Voltage in a transformer
Replies
9
Views
2K
Transformer equations in the Hughes book
Replies
2
Views
2K
Resulting magnetic flux in the core of a transformer
Replies
3
Views
3K
Transformer with attached load: required source voltage
Replies
5
Views
3K
Transformer Load Regulation Old Exam Question Help
Replies
6
Views
2K
Maximum Power Transfer Ideal Transformer
Replies
6
Views
3K

Hot Threads

Recent Insights

Back
Top