An Interesting Gravitation Problem

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Homework Help Overview

The problem involves two satellites launched from a planet with negligible radius, focusing on their respective orbits. The first satellite is launched at a speed \(v_0\) and enters a circular orbit, while the second satellite is launched at half that speed, \(\frac{1}{2}v_0\). The objective is to determine the minimum distance of the second satellite from the planet during its orbit.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using energy conservation and angular momentum to analyze the motion of the satellites. There is an exploration of the relationship between potential and kinetic energy for both satellites. Questions arise about the conditions for the second satellite's minimum distance from the planet and the significance of tangential velocity at that point.

Discussion Status

Some participants have suggested methods involving conservation laws to derive relationships between the variables. There are ongoing inquiries about the geometric and physical implications of tangential velocity at the lowest point of the second satellite's orbit, indicating a productive exploration of the topic.

Contextual Notes

Participants are working within the constraints of the problem as stated, including the assumption of negligible planetary radius and the specific speeds of the satellites. There is a focus on understanding the implications of these conditions on the motion of the satellites.

k1point618
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Homework Statement


Two satellites are launched at a distance R from a planet of negligible radius. (Yes, that's what the problem says...) Both satellites are launched in the tangential direction. the first satellite launches correctly at a speed v_0 and enters a circular orbit. The second satellite, however, is launched at a speed \frac{1}{2}v_0 . What is the minimum distance between the second satellite and the planet over the course of its orbit?


Homework Equations





The Attempt at a Solution


I thought about using energy. The two satellites both start out with the same potential energy but different kinetic energy.

So satellite one's TME: -\frac{GMm}{R} + \frac{1}{2}mv_0^2

where as satellite two's TME:-\frac{GMm}{R} + \frac{1}{8}mv_0^2

And the second satellite's minimum distance is when its potential is the least...
Somehow I think this problem might relate to angular momentum... L = mvr, but not exactly sure.

THANK YOU =D
 
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You can use the fact the first satellite goes into a circular orbit to figure out M in terms of R and v0 using the centripetal acceleration of an object in circular motion. Let R1 and v1 be the radius at the lowest point. At the lowest point v1 is again tangenential to the planet. So conservation of angular momentum gives you one equation in R1 and v1 and conservation of energy gives you another. Solve them simultaneously.
 
Ah, i c~

and i got it right =D

ThanX
 
Dick said:
You can use the fact the first satellite goes into a circular orbit to figure out M in terms of R and v0 using the centripetal acceleration of an object in circular motion. Let R1 and v1 be the radius at the lowest point. At the lowest point v1 is again tangenential to the planet. So conservation of angular momentum gives you one equation in R1 and v1 and conservation of energy gives you another. Solve them simultaneously.

How can you prove that the lowest point does indeed occur when the velocity is tangent again? And why do we need to know that it is tangent? Is something not conserved otherwise?
 
Last edited:
compwiz3000 said:
How can you prove that the lowest point does indeed occur when the velocity is tangent again? And why do we need to know that it is tangent? Is something not conserved otherwise?

The lowest point occurs when the object is traveling 'horizontally' i.e. perpendicular to the radial vector connecting the object to the planets center. Draw a picture. Knowing the angle between those vectors makes it easy to compute angular momentum. Try it.
 
haha I forgot that angular momentum is a cross product
 

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