Angle of refraction through ice into water

AI Thread Summary
To determine the angle of refraction of light passing from ice into water, Snell's law must be applied at both interfaces. The refractive index of ice and water is essential for accurate calculations. First, calculate the angle of refraction in the ice using the angle of incidence of 15.0°, then use that result as the angle of incidence for the transition into water. The parallel nature of the ice does not affect the application of Snell's law, as it applies at each surface. This method ensures a correct understanding of how light bends at each interface.
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Homework Statement



A layer of ice having parallel sides floats on water. If light is incident on the upper surface of the ice at an angle of incidence of 15.0°, what is the angle of refraction in the water?

Homework Equations





The Attempt at a Solution


i know its not so simple that i can just use Sin theta n1 = sin theta n2... but i don't know how the fact that it is parallel will change the equation. Should i find the angle of refraction in the ice and then use that as the angle of incidence for the water?
 
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The equation only applies at a point on the surface - being parallel just means that you don't care where on the surface.

It's almost the same as the typical experiment with light going through a glass block.
You simply apply Snell's law ( n1 sin t1 = n2 sin t2 ) at each surface.
You will need the refractive index of ice and remember which way light bends at each surface.
 
goWlfpack said:
Should i find the angle of refraction in the ice and then use that as the angle of incidence for the water?

Yup. That's how you should go about this problem. Use Snell's law twice, once at each interface.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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