Angular energy vs translational energy

Click For Summary

Homework Help Overview

The discussion revolves around the concepts of angular energy and translational energy in the context of a rectangular block tipping over a pivot point. Participants explore the conditions under which the block exhibits rotational and translational kinetic energy as it falls to the ground.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants question the nature of kinetic energy as the block tips and lands, considering both translational and rotational components. They discuss the impact of friction on the motion of the block and whether the center of mass moves horizontally or vertically during the fall.

Discussion Status

There is an active exploration of the relationship between translational and rotational kinetic energy, with participants providing insights into how friction influences these energies. Some participants express understanding of the concepts, while others continue to seek clarification on specific scenarios, such as the effects of friction and the conditions for translational motion.

Contextual Notes

Participants are considering various scenarios, including the presence or absence of friction and the implications for the block's motion. There is an emphasis on understanding the roles of the center of mass and the pivot point in determining the energy types involved.

GnG.Vike13
Messages
11
Reaction score
0
i don't understand this at all... if we tip over a rectangular block (such that a corner is its pivot), will it have rotational kinetical energy, translational kinetic energy, or both when it hits the ground?
 
Physics news on Phys.org
Ask yourself "Is its centre of mass moving horizontally and or vertically with respect to the floor when it actually lands and is it rotating?"
How would things be different if there were no friction between the corner and the table (assuming you placed it just beyond its tipping angle?
What does that tell you about its translational and rotational KE, bearing in mind that the same amount of energy is available in each case.
 
Last edited:
so the translational kinetic energy is based on its center of mass' velocity and the rotational energy is based on the I of the whole block and w?

and, just to be clear, the weight vector will always come from the center of mass, correct?

also, how would friction play into this? would it be at the axis of rotation, thus causing not torque, but preventing it from making a translational acceleration?
 
GnG.Vike13 said:
so the translational kinetic energy is based on its center of mass' velocity and the rotational energy is based on the I of the whole block and w?

and, just to be clear, the weight vector will always come from the center of mass, correct?

also, how would friction play into this? would it be at the axis of rotation, thus causing not torque, but preventing it from making a translational acceleration?

That seems the right idea. But there would be a definite difference if there were no friction. What would the block rotate around if the corner were allowed to slip? Would the cm ever be moving horizontally at all? Would the block take the same time to fall with and without friction?
Your statements about mvsquared/2 and Iωsquared/2 are obviously correct. I think the only way that there would be no translational energy would be if it were just a couple that was applied to the block so that the cm was not moving in any direction. This is definitely not the case here.
 
sophiecentaur said:
That seems the right idea. But there would be a definite difference if there were no friction. What would the block rotate around if the corner were allowed to slip? Would the cm ever be moving horizontally at all? Would the block take the same time to fall with and without friction?
Your statements about mvsquared/2 and Iωsquared/2 are obviously correct. I think the only way that there would be no translational energy would be if it were just a couple that was applied to the block so that the cm was not moving in any direction. This is definitely not the case here.

okay, it's good to know that i understand this. one more question, perhaps.

what happens if the block isn't tipping over and the frictional force is applied completely on block's bottom side? how do you look at the problem then?
 
Then, with sufficient force applied, won't it just slide with some translational KE and no rotational energy?
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
3K
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K