Angular momentum merry go round

AI Thread Summary
The discussion revolves around calculating the angular velocity of a merry-go-round when a person runs at a speed of 4.1 m/s on its edge. The initial angular momentum is zero, and the final angular momentum is expressed as the difference between the person’s and the turntable’s contributions. The key issue identified is that the speed of the person is given relative to the turntable, necessitating a conversion to angular velocity for accurate calculations. Participants emphasize the need to determine the angular velocity of the person with respect to the ground and then use that to find the turntable's angular velocity. The conversation highlights the importance of correctly applying conservation of angular momentum principles in this scenario.
sumitmanhas
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Homework Statement


Suppose a 74 kg person stands at the edge of a 6.6 m diameter merry-go-round turntable that is mounted on frictionless bearings and has a moment of inertia of 1820 kg.m^2. The turntable is at rest initially, but when the person begins running at a speed of 4.1 m/s (with respect to the turntable) around its edge, the turntable begins to rotate in the opposite direction.
Part A
Calculate the magnitude of the angular velocity of the turntable.


Homework Equations


conservation of angular momentum


The Attempt at a Solution


this is how i approached it.
initial angular momentum = 0
final anglar momentum = I(\omegaP) - I(\omegaT)

while \omegap = v/r and IP = MR2

MR2V/R - I(\omegaT) = 0

\omegaT = MRV/IT

\omegaT = (74)(3.3)(4.1)/ 1820

\omegaT = 0.55 RAD/S

but due to some reason turns out to be the wrong answer , someone please help ??
 
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The speed of the person is given with respect to the turntable, not with respect to the ground (which is what you need).

Hint: If the angular speed of the turntable (with respect to the ground) is ω, what would be the angular speed of the runner with respect to the ground?
 
what i think is that angular velocity of the person with respect to ground = 4.1 + angular velocity of table
can be wrong though...someone reply as soon as possible this question is due within an hour
 
sumitmanhas said:
what i think is that angular velocity of the person with respect to ground = 4.1 + angular velocity of table
can be wrong though...someone reply as soon as possible this question is due within an hour
Almost. But 4.1 m/s is a linear speed, not an angular velocity. Convert it to an angular velocity first.
 
but what would be the angular velocity of the turntable then for finding the angular velocity of the person with respect to ground . do i use then one i calculated at my first attempt . and then plug it into equation for finding the angular velocity of person with respect to ground.??

and then after finding the angular velocity of the person with respect to ground u plug it back into the very first equation for finding angular velocity of the table.
tried this whole thing but never worked.

help ??
 
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