Angular momentum to linear velocity

chiefjslay
Messages
4
Reaction score
0
Im stuck on this problem and I've gotten to the point where I am just staring at my computer, so I figured Id give you guys a go at it.

I got Part A which was fairly simple. But I've tried everything but can't seem to get Part B. I must be missing something. This is one of those online assignments where you get as many attempts as you want. I keep getting Part A, but can't get Part B. Please explain how you did Part B if you get it. I have the correct answers too.

In Fig. 11-52, a 7.3 g bullet is fired into a 0.46 kg block attached to the end of a 0.12 m nonuniform rod of mass 0.88 kg. The block-rod-bullet system then rotates in the plane of the figure, about a fixed axis at A. The rotational inertia of the rod alone about A is 0.038 kg·m2. Treat the block as a particle. (a) What then is the rotational inertia of the block-rod-bullet system about point A? (b) If the angular speed of the system about A just after impact is 7.2 rad/s, what is the bullet's speed just before impact?

Fig11_52.gif
 

Attachments

  • Fig11_52.gif
    Fig11_52.gif
    2.1 KB · Views: 601
Physics news on Phys.org
anybody have any hints? I know about conservation of momentum. And I know MV=Iw. I am pretty sure I need to convert units of w to m/s but I don't think I am doing it right.
 
Remember the angular momentum of a point mass about an axis is simply the linear momentum times the distance from the axis, i.e. p*r = mvr.

The block and the bullet are point masses. Can you proceed ?
 
Nevermind I figured it out. It was a stupid error on my part. I simply had to divide the rad/s by the radius to get the correct units.
 
Thanks for helping though, Curious
 
chiefjslay said:
anybody have any hints? I know about conservation of momentum. And I know MV=Iw. I am pretty sure I need to convert units of w to m/s but I don't think I am doing it right.

Have a care. You may be able to get the right answer by converting units, but the equation MV=Iw is incorrect as it stands. You cannot equate linear and angular momentum. They have different units. What you have done in "converting units" is change your equation (to the correct one, if I am guessing correctly.) Make sure you know what this equation is and how to use it!

-Dan
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top