Calculating Angular Velocity of a Shell Exiting a Barrel | Physics Homework

AI Thread Summary
To calculate the angular velocity of a shell exiting a barrel, the initial velocity is given as 320 m/s, with the shell making 2 turns in a barrel length of 2.0 m. The relevant equations for linear and angular motion are provided, including vf = vi + at and vf^2 - vi^2 = 2ax. The discussion emphasizes the need to determine the time taken for the shell to complete the 2 turns, denoted as ts, to find the angular velocity. The angular velocity can be expressed in terms of ts, and the conversion from turns to radians is also noted, as 2 turns equal 4π radians. The final angular velocity is calculated to be 2.0 x 10^3 rad/s.
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Homework Statement


A shell acquires the initial velocity v = 320m/s, having made n = 2.0 turns inside the barrel whose length is equal to l = 2.0m. Assuming that the shell moves inside the barrel with uniform acceleration, find the angular velocity of its axial rotation at the moment when the shell escapes the barrel.

Homework Equations


vf = vi + at
This equation can be used for linear as well as angular velocity
x = vit + at^2
vf^2 - vi^2 = 2ax

The Attempt at a Solution


The given answer is 2pi nv/l = 2.0 x 103 rad./s
 
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How much time it took to make those n = 2 turns? then if you know this time, can you find angular velocity?
 
housemartin said:
How much time it took to make those n = 2 turns? then if you know this time, can you find angular velocity?

Time is not given. But let us consider it take ts for n = 2 turns. can we get the answer in terms of t?
 
Time is what you have to find, you know final ant initial linear velocities and the length of the barrel, from here you can find ts. Angular velocity is measured in radians per second. And two rotations is how much radians? And you when you find time it took to make those two rotations, then...? ;]
 
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