Engineering Another circuit task, but tricky.

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The discussion focuses on calculating the current and voltage drops in a circuit with a voltaic element. The electromotive voltage is 1.1V, with an internal resistance of 1 ohm and an external resistance of 9 ohms. The current is calculated using the formula I = E/(r + R), resulting in 0.11A. Voltage drops across the external and internal resistors can be found by multiplying the current by their respective resistances. The total voltage drops should equal the voltage of the source, confirming the calculations are correct.
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Homework Statement


A voltaic element with electromotive voltage E=1,1V and with internal resistance r=1ohm, is connected to an external resistor with the resistance R=9ohm. Determine the current I which circulates in the circuit, also the falls of voltage on the external portion of the circuit VR and on the internal portion of the circuit Vr. Also, at what yield the voltaic element works?

Homework Equations


I=V/R

I=E/(r+R)

The Attempt at a Solution



The first step is easy, I mean calculating the I (I=E/(r+R)=1,1/(1+10)=0,11), but then I have some doubts.. Will it be right to calculate VR as VR=I*R and Vr as Vr=I*r? or maybe I must reduce something because it says: "the falls of voltage" so there should be a higher value and a smaller one.
 
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lymos said:

Homework Statement


A voltaic element with electromotive voltage E=1,1V and with internal resistance r=1ohm, is connected to an external resistor with the resistance R=9ohm. Determine the current I which circulates in the circuit, also the falls of voltage on the external portion of the circuit VR and on the internal portion of the circuit Vr. Also, at what yield the voltaic element works?


Homework Equations


I=V/R

I=E/(r+R)

The Attempt at a Solution



The first step is easy, I mean calculating the I (I=E/(r+R)=1,1/(1+10)=0,11), but then I have some doubts.. Will it be right to calculate VR as VR=I*R and Vr as Vr=I*r? or maybe I must reduce something because it says: "the falls of voltage" so there should be a higher value and a smaller one.

It looks like you are doing it correctly. You calculated the current correctly, so now you get each individual voltage drop across each resistor by multiplying the current by each individual resistance. You can check your answers, because the sum of the voltage drops across the resistors must equal the value of the voltage source, correct?
 

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