What is the lowest m where 520 nm light disappears in a 6000 lines/cm grating?

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The discussion focuses on determining the lowest order m for which 520 nm light disappears when passing through a diffraction grating with 6000 lines/cm. The relevant equation for this analysis is sin(theta(m)) = m(wavelength)/d, where d is the grating spacing. The light will no longer be observable when the angle theta_m exceeds 90 degrees. To find the maximum order, one must calculate the number of orders possible for the given wavelength. Ultimately, the disappearance of the 520 nm line occurs when the calculated m exceeds the maximum value that keeps theta_m within the valid range.
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Lights with wavelengths of 520 nm and 630 nm passess through a diffraction grating that contains 6000 lines/cm or 600000 lines/m

what is the lowest value of m for which the 520 nm line no longer exists?
 
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where do i start with this...
 
Do you know any equations relating to diffraction gratings?
 
sin theta(m) = m(wavelength)/ d
 
Well all you have to do is find out how many orders you can get for that wavelength. You know when it disappears when \theta_m is greater than 90 degrees.
 
thank you very much..
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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