Answer: Are Pln & Line Othogonal/Parallel? Solution to (-x+2z=10)

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Homework Statement



Determin if the plan given by (-x+2z=10) and the line given by r=<5,2-t,10+4t> are othogonal,parllel or neither??

What is the solution?
 
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I'm not going to give you the solution- the point is for you to find the solution. I will suggest this: your line is given by the vector equation r= <5, 2, 10>+ t<0,-1,4> so <0, -1, 4> is a vector pointing in the direction of that line. Also, the plane -x+ 0y+ 2z= 10 has <-1, 0, 2> as normal vector (that is <-1, 0, 2> is perpendicular to the plane).

What must be true of those two vectors in order that the line and plane be perpendicular? parallel? Are those true?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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