Answer: Find Moments & Reactions for Force Couple on Frame

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Discussion Overview

The discussion revolves around analyzing a force couple acting on a fixed frame, specifically focusing on finding the moments and reactions at fixed locations. The context is primarily homework-related, involving static equilibrium equations and assumptions regarding the behavior of the frame under applied forces.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the reactions are equivalent to the acting forces (1430 lbs) and proposes that points of inflection exist halfway along the length of the legs, leading to a theoretical "pinned" connection at the center.
  • Another participant challenges the first post by stating that the moment calculation ignores the opposing force of 1430 lbf at the corner above point B.
  • A subsequent post questions the internal shear force in the horizontal member if it were cut in half, expressing confusion over the balance of forces given the reactions and applied forces.
  • Another participant critiques the assumption of a point of zero moment occurring halfway up the columns, arguing that the conditions at the top and bottom of the columns differ significantly and suggesting that the assumption of zero bending moment is more credible at the beam connection, while acknowledging the potential for torsional moments.

Areas of Agreement / Disagreement

Participants express differing views on the assumptions made regarding moments and forces in the frame, indicating that there is no consensus on the validity of the initial assumptions or the calculations presented.

Contextual Notes

There are unresolved questions regarding the assumptions made about the points of zero moment and the behavior of the horizontal member under the applied forces, as well as the implications of the frame's fixed conditions.

gomerpyle
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Homework Statement


A force couple acts on the frame, which is fixed at the base. Find the moment(s) and reaction(s) at the fixed locations.

Homework Equations


ΣMa = 0
ΣMb = 0
ΣFy = 0
ΣFx = 0

The Attempt at a Solution


Since it would be statically indeterminate, assumptions would be that the reactions are equivalent to the acting forces (1430 lbs), and points of inflection exist halfway along the 25.5" length of the legs? This results in a theoretical "pinned" connection at the center thus the FBD for one leg cut in half:

ΣMa = -(12.75)*1430 + Ma = 0
Ma = 18232 in-lbs

Obviously both moments have to be equal, so Mb = 18232 in-lbs.

Am I on the right track? Wouldn't there be a Torsional reaction as well? I'm just a little lost because all the examples of frames I can find don't have forces acting perpendicular to the plane of the members (acting "into the page").
 

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Your ΣMa ignores the 1430 lbf in the other direction (at the corner above B)

What if the horizontal member were cut in half ?
 
So if it were cut in half what would be the internal shear force acting on it? My guess would be 1430, but then if you did a force balance it wouldn't make sense because you already have the reaction at the base as 1430, and then the applied 1430 in the opposite direction. That would mean the force in the horizontal member would have to be zero?
 
The assumption that a point of zero moment occurs half-way up the columns is unconvincing, because the conditions at the top and the bottom of the columns are not the same; at the bottom it is encastre and no rotation is assumed to occur, but at the top of the columns, the fixity is provided by a connection to a flexible member (the beam) where rotations about the x,y and z axes are possible. the assumption that a point of zero bending moment occurs half-way along the beam is more credible. However that would be accompanied by a torsional moment there (constant along the beam length). I am thinking qualitatively here, and am aware that careful calculations done properly can reveal errors in thinking at the same time as teaching us something.
 

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