AP Free - Response Question HELP iNCLUDES angular velocity and acceleration

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SUMMARY

The discussion centers on solving a physics problem from the AP Free Response exam, specifically focusing on angular velocity and acceleration. The user struggles with calculating the tension in a string using the equation T = mg + Iωr and expresses confusion regarding the application of angular acceleration and the relationship between angular and linear velocity. The user seeks clarification on these concepts to ensure accurate problem-solving and understanding of the mechanics involved.

PREREQUISITES
  • Understanding of angular velocity and acceleration
  • Familiarity with moment of inertia and its role in rotational dynamics
  • Knowledge of the relationship between linear and angular motion
  • Basic principles of tension in strings and forces in mechanics
NEXT STEPS
  • Review the concept of tension in strings and its applications in mechanics
  • Study the relationship between angular acceleration and moment of inertia in rotational motion
  • Learn how to convert between linear and angular velocity in physics problems
  • Practice solving AP Free Response questions related to rotational dynamics
USEFUL FOR

High school physics students preparing for the AP exam, educators teaching mechanics, and anyone looking to strengthen their understanding of angular motion and tension in strings.

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AP Free - Response Question HELP! iNCLUDES angular velocity and acceleration

http://www.fayar.net/east/Teacher.web/Math/young/APPC/APPC%201999/physics_c_m_99.pdf

Mechanics 3 is the problem I really need help on.
I tried to find the tension of the string by setting it equal to mg + Iwr, but I'm not sure if I'm doing it right! On part b, I set the angular acceleration equal to the initial angular velocity + moment of inertia, and I got through canceling some factors. On part c, I set the angular velocity equal to the linear velocity times the time.

I NEED HELP ON HOW TO DO IT RIGHT! I THINK I'M TOTALLY DOING IT WRONG BECAUSE MY ANSWERS SEEM TO BE WAY OFF!
 
Last edited by a moderator:
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Its a string, so it can only support load in the axial direction.
 
Is current used up in a resistor? Explain
 

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