Applications of the Equations of Kinematics

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Homework Help Overview

The discussion revolves around a kinematics problem involving the acceleration of blood in the heart, specifically calculating acceleration and time based on given displacement and final velocity. The original poster seeks clarification on the formulas involved in solving the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of kinematic equations, with one participant attempting to clarify the formula for acceleration and time. There is also a mention of the Work Energy theorem as a potential approach.

Discussion Status

Some participants have provided calculations for acceleration and time, but there is a discrepancy in the time value, indicating ongoing exploration of the problem. The conversation reflects attempts to verify and clarify the reasoning behind the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is a focus on ensuring clarity in the formulas and calculations involved.

amiemgm
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Homework Statement


Please help me with this problem. If you could at least give me the formula I could probably figure it out. I have worked out all of my homework but this one.

Please type out the formula in word form. I have a hard time figuring out what is squared and what all is under the division symbol, ex. (x= v^2 - vo^2 / 2a) displacement equals (final velocity squared minus initial velocity squared) divided by (2 times acceleration). Thanks I greatly appreciate it.

Question:
The left ventricle of the heart accelerates blood from rest to a velocity of +27 cm/s.

(a) If the displacement of the blood during the acceleration is +1.9 cm, determine its acceleration (in cm/s2).

(b) How much time does it take for the blood to reach its final velocity? (in seconds)




Homework Equations





The Attempt at a Solution

 
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Work Energy theorem. Work done equals energy. (Force)x(Distance)= 1/2 (mass)(velocity)^2.

Take mass out of each side of the equation. You have this written already, just apply it.

Under constant acceleration, Velocity equals acceleration x time.
 
Thanks,

I got 192 cm/s^2 for answer to A. And 14 s for answer to B. Seems like they would have asked for time first since I used it to figure out the acceleration.

Thanks again
 
Actually, the time should be 0.14 s, I'm pretty sure. Here is the equation I used to calculate time: v = vo + at (final velocity is equal to initial velocity plus acceleration times time). Therefore, t = v - vo/a, which yields 0.14 s.
 

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