Archimedes' principle -- Which box will sink first as we add coins....

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The discussion revolves around determining which of five identical-weight boxes will sink first as coins are added, based on Archimedes' principle. Participants consider the relationship between box volume and water displacement, noting that the box displacing the most water can hold the most coins before sinking. One participant suggests that the shape of the box affects how it sinks when coins are added simultaneously, prompting a thought experiment about the differences between long, slim boxes and wider, shorter ones. Ultimately, the consensus is that the box's volume above the water level is crucial to solving the problem. The conversation highlights the complexity of the scenario while reaffirming the principle of water displacement.
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There are five empty box contains with the same weight. The upper side of each boxes are removed. These boxes are floating in a pool of water. Then to each box we put coins slowly one by one. Assuming the box does not tilt. Determine which of the following size of the box (p x l x t) can be filled with most coins before it sinks.

A.) 4 x 4 x 11 cm3
B.) 6 x 6 x 6 cm3
C.) 8 x 8 x 4 cm3
D.) 10 x 10 x 2 cm3
E.) 12 x 12 x 1 cm3

Don't have the answer, but I chose C as the answer. All boxes have the same weight. The box with the larger volume should be able to float better than the other boxes right?
 
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Right.
 
I think it might be a little more complicated than that. Imagen that you add the same amount of coins to all the boxes at once and they all are sinking down. What do you think will happen?
 
andrevdh said:
I think it might be a little more complicated than that. Imagen that you add the same amount of coins to all the boxes at once and they all are sinking down. What do you think will happen?
First off you are changing the problem that says that the coins are added one at a time. However, I will imagine (as you asked me to do) that the same amount of coins are added to all boxes and that they all sink down. What I think will happen (as you said) is that they will all sink down. The point of the problem as stated is that the box that displaces the most water will hold the highest number of coins. Your point is ... ?
 
I was just engaging with the problem throught a thought experiment and wondering what will be the difference between long slim boxes and fat low boxes as they sink while they hold the same amount of coins in order to get a better feeling for the problem, but you are right because the volume above the water level actually holds the answer to this problem.
 
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