Are Orthogonal Vectors Proven by Derivative and Dot Product?

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    Orthogonal Vectors
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Homework Help Overview

The discussion revolves around proving that the derivative of a vector with constant magnitude is orthogonal to the vector itself. The context involves concepts from vector calculus, specifically focusing on derivatives and dot products.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the derivative of a vector and its orthogonality based on the dot product. There is a focus on clarifying the distinction between a vector having constant magnitude versus being a constant vector.

Discussion Status

Some participants have offered insights into the interpretation of the problem, with one noting a misreading of the question regarding the nature of the vector. The discussion appears to be progressing with clarifications being made, but no consensus or final conclusions have been reached.

Contextual Notes

Participants are navigating the implications of the vector's constant magnitude and its derivative, questioning assumptions about the nature of the vector involved in the problem.

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Homework Statement
Prove that if v(t) is any vector that depends on time, but v(t) has constant magnitude, then
v˙(t) is orthogonal to v(t)
Relevant Equations
Dot Product
I feel like this question is very straight forward and my explanation below summarizes the answer pretty well. Could someone confirm this or tell me if I am missing something?

We have V which is a vector, but the question states it is a constant. If I take the derivative of V, represented by V', a constant, then I get 0.
If I dot product these to values, the product is then 0. And it is known that when the dot product between two vectors is zero, they are orthogonal.
 
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quittingthecult said:
Homework Statement:: Prove that if v(t) is any vector that depends on time, but v(t) has constant magnitude, then
v˙(t) is orthogonal to v(t)
Relevant Equations:: Dot Product

I feel like this question is very straight forward and my explanation below summarizes the answer pretty well. Could someone confirm this or tell me if I am missing something?

We have V which is a vector, but the question states it is a constant. If I take the derivative of V, represented by V', a constant, then I get 0.
If I dot product these to values, the product is then 0. And it is known that when the dot product between two vectors is zero, they are orthogonal.
It says that ##\vec v## has constant magnitude; not that ##\vec v## is constant.
 
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PeroK said:
It says that ##\vec v## has constant magnitude; not that ##\vec v## is constant.
Ah I misread the question. That makes a lot of sense. Thank you for catching that.
 
So what does it look like now?
 
BvU said:
So what does it look like now?
IMG_0311.jpg
This is the conclusion I came to.
 
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