Astronaut's Maximum Distance from Shuttle Due to Line Breakage

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The discussion centers on a physics problem involving an astronaut who must return to her shuttle after her tether breaks. The astronaut throws an oxygen tank to propel herself back, and the calculations involve determining her maximum distance from the shuttle within a 52.2-second timeframe. The initial calculations incorrectly applied a distance formula meant for uniformly accelerated motion instead of one for constant velocity. The correct approach requires using the constant velocity formula to find how far she can travel in that time. Ultimately, the focus is on correcting the distance calculation based on the astronaut's velocity after throwing the tank.
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Homework Statement


A 63.1 kg astronaut is on a space walk away from the shuttle when her tether line breaks.
She is able to throw her 12.9 kg oxygen tank away from the shuttle with a speed of 10.4m/s
to propel herself back to the shuttle. Assuming that she starts from rest (relative to the shuttle), determine the maximum distance she can be from the craft when the
line breaks and still return within 52.2 s (the amount of time she can hold her breath). Answer in units of m.

I'm getting the wrong answer to this problem. can someone help me figure out where i went wrong?
This is what I did:
1. Found out what Vf for astronaut would be:
MaVfa= Moxygentank(Vf)
MoVfo/ Ma = Vfa
Vfa= 2.12614897 m/s
2. then i decided to use the distance formula
d= Vi + Vf/2 (t)
where Vi= 0 and Vf= the answer above and t= 52.2s
i got d= 55.49248811m
 
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Your distance formula is for uniformly accelerated motion. This is motion at a constant velocity. How far can you get in 52.2s at a constant velocity of 2.126m/s?
 
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