Astrophysics - Apparent Magnitude of stars in a close binary system

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SUMMARY

The apparent magnitude of a close binary system consisting of two solar-type stars, each with an individual apparent brightness of m = 10 mag, is calculated to be approximately 4.25 mag when both stars are combined and not resolved. The calculation utilizes the formula m1 - m2 = -2.5 log(f1/f2) to determine the combined brightness. The discussion also addresses the minimum brightness during eclipses at 100%, 75%, 50%, and 25% coverage of the stellar surface, emphasizing that a change in brightness corresponds to a change in magnitude of less than 1 mag when two stars are involved.

PREREQUISITES
  • Understanding of apparent magnitude and its calculation in astrophysics
  • Familiarity with logarithmic functions and their application in brightness calculations
  • Knowledge of binary star systems and their characteristics
  • Basic grasp of eclipsing binaries and their effects on observed brightness
NEXT STEPS
  • Study the concept of logarithmic scales in astronomy, particularly in relation to brightness
  • Learn about the properties and dynamics of eclipsing binary systems
  • Investigate the effects of varying surface coverage on the apparent magnitude of stars
  • Explore the use of photometric measurements in determining stellar brightness
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Astronomy students, astrophysicists, and educators seeking to deepen their understanding of binary star systems and the calculation of apparent magnitudes in astrophysics.

goldilocks
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Homework Statement



2 solar type stars are in a close binary system. Each indivual star has an apparent brightness of m = 10 mag.

Determine the apparent magnitudes of the combined system of the 2 stars assuming they cannot be resolved as individual objects. Determine the minimum brightness for this eclipsing binary when 100%, 75%, 50% and 25% of the stellar survace are covered during the eclipse.

Homework Equations



m1 - m2 = -2.5 log(f1/f2)

The Attempt at a Solution



m1 - m2 = -2.5 log (f1/f2)
10-10 = -2.5log(f1/f2)
f1/f2 =1
f1=f2

m1+2 - m2 = -2.5 log (f1+f2 \ f2) f1 = f2
m1+2 - m2 = -2.5 log (2f1 \ f1)
m1+2 - m2 = -2.5 log 2
m1+2 = -2.5log2 + 5 mag
m1+2=4.247425011
m1+2 = 4.25 mag

Then I'm not sure how to continue from here - any help would be most appreciated!
 
Physics news on Phys.org
One magnitude represents a change in brightness of a factor of around 2.5
so if you double the brightness (ie two stars) the apparent mag of the combination is only going to change by less than 1mag
 

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