At what rate is the flywheel spinning when the power comes back on?

Click For Summary
SUMMARY

The discussion focuses on calculating the rate of a flywheel's spin after a power failure. Initially spinning at 500 rpm, the flywheel, with a mass of 36.0 kg and a diameter of 75.0 cm, slows down to 135.3 rpm over 34 seconds due to friction. During this time, it completes 180 revolutions, indicating an average speed of 317.65 rpm. The calculations reveal that if the power had not returned, the flywheel would have taken approximately 12.6 seconds to come to a complete stop.

PREREQUISITES
  • Understanding of angular velocity and revolutions per minute (rpm)
  • Knowledge of angular deceleration and its calculation
  • Familiarity with the equations of motion for rotational dynamics
  • Basic physics concepts related to friction and energy loss
NEXT STEPS
  • Study the equations of motion for rotational dynamics, focusing on angular acceleration
  • Learn about the effects of friction on rotational motion
  • Explore the concept of angular momentum and its conservation
  • Investigate real-world applications of flywheels in energy storage systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of rotational systems and energy loss in mechanical components.

nguyenn2
Messages
5
Reaction score
0
Physic help urgent

A high-speed flywheel in a motor is spinning at 500 when a power failure suddenly occurs. The flywheel has mass 36.0 and diameter 75.0 . The power is off for 34.0 and during this time the flywheel slows due to friction in its axle bearings. During the time the power is off, the flywheel makes 180 complete revolutions.

a)At what rate is the flywheel spinning when the power comes back on?

b)How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on?

c)How many revolutions would the wheel have made during this time?

my work
avg speed = distance / time the time is 34 sec * ( 1 min / 60 sec ) = 0.566667 min

and avg speed = 180 rev / 0.56667 min = 317.65 rpm

the average speed is the average of the initial and final, so the final and initial together must equal 2 * 317.65 = 635.3 rpm

Since initial is 500, the final must be 135.3 rpm

The flywheel slowed from 500 to 135.3 rpm in 34 sec or:

(500 - 135.3) / 34 = 10.73 rpm every sec

: 135.3 ( 1 sec / 10.73 rpm) = 12.6 seconds to bring the wheel to rest.

the avg speed would be (1/2) ( 135.3 + 0 ) = 67.65 rpm

so the wheel would go 67.65 rpm * 12.6 sec ( 1 min / 60 sec) = 14.2 revoluti
 
Physics news on Phys.org
im getting the wrong answers
 
This problem should rather be attempted with the constant angular acceleration equations

http://www.saburchill.com/physics/chapters/0023.html"

http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html"

http://electron9.phys.utk.edu/phys135d/modules/m8/rotation.htm"

Hint: Use the data from the off period to calculate the angular deceleration of the flywheel.
 
Last edited by a moderator:

Similar threads

  • · Replies 16 ·
Replies
16
Views
12K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 43 ·
2
Replies
43
Views
6K
  • · Replies 8 ·
Replies
8
Views
8K
  • · Replies 6 ·
Replies
6
Views
9K
Replies
2
Views
31K
  • · Replies 18 ·
Replies
18
Views
4K
Replies
1
Views
2K
  • · Replies 27 ·
Replies
27
Views
7K
  • · Replies 2 ·
Replies
2
Views
3K