Atwood machine, solve for angular acceleration

AI Thread Summary
To solve for angular acceleration in an Atwood machine involving two masses and a pulley, it's essential to relate the angular acceleration of the pulley to the linear acceleration of the masses. The net torque on the pulley equals the moment of inertia times the angular acceleration, while the net force on the masses equals their mass times linear acceleration. The linear acceleration of the masses is directly related to the angular acceleration of the pulley through the radius of the pulley. Understanding that the tangential acceleration at the pulley’s circumference is equal to the linear acceleration of the masses is crucial for solving the problem. Clarifying these relationships helps in accurately determining the angular acceleration.
aznboi855
Messages
11
Reaction score
0

Homework Statement


The goal is to solve for angular acceleration with the end variables being m1,m2,m3, R, r, g.
M2 > M1.
An atwood machine is a pulley with 2 masses, one on each side.


Homework Equations


Tnet = I * angular acceleration
Fnet = ma

The Attempt at a Solution


I know you have to solve for both the masses and the pulley itself, but how do you relate them?
 
Physics news on Phys.org
How does the angular acceleration of the pulley relate to the linear acceleration of the masses?
 
It's the same?
 
aznboi855 said:
It's the same?
:confused: How can an angular acceleration be the same as a linear acceleration? (But they are simply related though.)
 
I must've misunderstood your question, I simply thought that because the mass is having a linear acceleration downward, therefore causing the pulley to have an angular acceleration, they must be the same :S. I'm bad at this angular stuff :(.
Angular acceleration the change in angular velocity over time, and angular velocity is the change in angle over time... so... I still can't relate them :S.
 
Hint: Given the angular acceleration of the pulley, what's the tangential acceleration along its circumference?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Working out the accelerations in a double Atwood pulley system
Replies
22
Views
1K
Angular acceleration of an atwood pulley
Replies
8
Views
4K
How Do You Solve a Double Atwood Machine Problem with Unequal Masses?
Replies
1
Views
3K
Atwood's Machine: Understanding Acceleration and Tension
Replies
10
Views
3K
An Atwoods Machine hanging from the ceiling
Replies
29
Views
5K
Accelerating pulleys (3 pulleys and 3 masses)
Replies
5
Views
2K
Analyzing acceleration of block on a ramp connected to a pulley
Replies
15
Views
1K
Effects of Rolling Resistance on Tension and Acceleration in an Atwood Machine
Replies
2
Views
2K
Negative Moment of Inertia from Atwood Machine Experiment?
Replies
13
Views
4K
Atwood Machine: Find M in Terms of m1 & m2
Replies
3
Views
3K

Hot Threads

Recent Insights

Back
Top