Atwood's fall machine w. sylinder (again?)

  • Thread starter Thread starter center o bass
  • Start date Start date
  • Tags Tags
    Fall Machine
Click For Summary

Homework Help Overview

The problem involves Atwood's fall machine, which consists of two weights connected by a massless rope over a spinning wheel. The task is to find the velocity of each weight as a function of their vertical positions, considering the system's energy dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of energy considerations and the implications of having two masses on either side of the wheel. Questions arise about calculating the total potential energy and how to account for the individual velocities of the masses.

Discussion Status

Some participants have offered guidance on focusing on the change in potential energy for each mass. There is recognition that the velocities of the masses must be the same and that kinetic energy considerations include both the masses and the rotational energy of the wheel. However, uncertainty remains regarding the potential energy calculations.

Contextual Notes

Participants are navigating the complexities of energy conservation in a system with multiple components, and there is an emphasis on understanding the relationships between potential and kinetic energy in this context.

center o bass
Messages
545
Reaction score
2

Homework Statement



Atwood’s fall machine consists of two weight of mass m1 and m2 attached with a massless
rope running around a spinning wheel of mass M and radius R without slipping. The spinning wheel is attached at its center and rotates around an axis through its center without friction.

Find velocity of each of the weights as a function of their vertical positions.

Homework Equations


E = constant

The Attempt at a Solution


I'm assuming that one m1 < m2 so that the system will accelerate in the direction of where m2 is hanging.

I'm sure I should be using energyconsideration here, but the only thing I'm not sure how to attack is the fact that we have two masses on each side of the wheel. What is then my total potential energy to start with? I tought about focusing my attention on the center of mass, but then I don't see how I get the individual velocity of each of the masses.
 
Physics news on Phys.org
Hi center o bass! :wink:
center o bass said:
I'm sure I should be using energyconsideration here, but the only thing I'm not sure how to attack is the fact that we have two masses on each side of the wheel. What is then my total potential energy to start with? …

You're only interested in the change in PE …

just add the changes for each mass (one will be positive, and one negative, of course). :smile:
 
I realize that the velocity of each of the masses must be the same. And that kinetic energy therefore goes into each of the masses individually pluss the rotational kinetic energy of the wheel. But I still don't understand how to think about the potential energy... Just sitting there at the same height, they should have a potential energy of mgh each, but then I don't get the correct andswer.
 
Ah...! You said it ;) Thanks a lot!
 

Similar threads

Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 29 ·
Replies
29
Views
5K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K