Average crush force exerted on a car

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    Average Car Force
AI Thread Summary
The discussion centers on calculating the average crush force exerted on a car using kinetic energy principles. The formula proposed is Average crush force = mv^2 / 2d, where d represents the distance over which the force is applied. Participants agree that all kinetic energy is converted into work during the crushing process, represented by the equation W = Fd = 1/2*m*v^2. There is a request for a more detailed proof of the formula. The conversation emphasizes the relationship between kinetic energy, work, and force in the context of vehicle collisions.
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Homework Statement


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Homework Equations


Kinetic energy = Ke = (1/2)(mv^2) (joules - J)
where m = mass (kg)
v = velocity (m/s)

The Attempt at a Solution


What I was thinking was that the kinetic energy is divided uniformly over the distance d and hence
Average crush force = mv^2 / 2d

But I don't know how to prove that. Of course I could try to explain it with words, but I don't feel that it is enough.

Thank you in advance.
 
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All of the KE is converted to work in crushing things: W = Fd = 1/2*m*v^2
 
thank you, very helpful!
 
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