Baseball Kinematics: Calculating Acceleration from Stopping Distance

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To calculate the acceleration of a baseball that stops from 30 m/s in a distance of 5.0 cm, the equation Vf^2 = Vi^2 + 2a.d is used. Substituting the values gives -90 m^2/s^2 = 2a(0.05 m), leading to a calculated acceleration of -600 m/s^2. There is a caution about calculation accuracy, as errors can occur in the process. The discussion emphasizes the importance of careful arithmetic in physics problems. Properly applying the kinematic equations is essential for accurate results.
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Homework Statement



A baseball traveling at 30 m/s [f] hits a catcher's mitt and comes to a stop in a distance of 5.0 cm. What is the acceleration?

Homework Equations


The Attempt at a Solution


Vi = 30 m/s
d = 0.05 m
a = ?
Vf = 0

Vf^2 = Vi^2 + 2a.d
0 = 90 m^2/s^2 + 2a.0.05m
- 90 m^2/s^2 = 2a.0.05m
-30 m^2/s^2 = a.0.05m
a = -600 m/s^2
 
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novawinters said:
- 90 m^2/s^2 = 2a.0.05m
-30 m^2/s^2 = a.0.05m

90 divided by 2 is 45 :-p

ehild
 
The method is correct but be careful with calculations.
 

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