Is This Ohm's Law Application Correct for an OP-AMP Circuit?

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The discussion revolves around the application of Ohm's Law in an OP-AMP circuit, specifically questioning the correctness of an equation related to the circuit's upper loop. Participants express confusion regarding the identification of a rectangular component, debating whether it represents a capacitor or a resistor, with one suggesting it might be a resistor with a value of 1/S, where 'S' denotes the Laplace domain frequency variable. Clarification is provided that reactive components have specific impedances in the Laplace domain, and the importance of feedback resistors in differentiating and integrating OP-AMP configurations is highlighted. Ultimately, the rectangular component is confirmed to represent a 1 F capacitor. The conversation emphasizes the need for clear circuit definitions to accurately assess the equations involved.
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Homework Statement


Hi,

So I'm just curious whether or not the following statement is correct for the circuit shown. It's part of a bigger problem involving OP-AMPS, the part of the circuit shown is the upper loop connecting from the inverting to the output.

I was just having some doubts in my mind and wanted to confirm whether or not the equation i have written is correct.

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Homework Equations


Ohms Law. V = IR.

The Attempt at a Solution



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For the given component values it looks okay. Presumably the rectangular component is meant to represent a 1 F capacitor?
 
CoolDude420 said:

Homework Statement


Hi,

So I'm just curious whether or not the following statement is correct for the circuit shown. It's part of a bigger problem involving OP-AMPS, the part of the circuit shown is the upper loop connecting from the inverting to the output.

I was just having some doubts in my mind and wanted to confirm whether or not the equation i have written is correct.

View attachment 215789

Homework Equations


Ohms Law. V = IR.

The Attempt at a Solution



View attachment 215790
Interestingly gneill seems to understand your circuit and terminology, but I am struggling with it. However, any way I look at it I can't see the rectangular component as being a capacitor unless the OP AMP in question is a differentiating OP AMP and even then I would need to see a feedback resistor which is a key part of the the various voltage components. Since we are doing V = IR (or in this case I = V/R) I cannot understand this to be differentiating problem, so I would read that the rectangular component is a resistor with a value of 1/S but I am not able to determine what 'S' signifies. Also, if this is an integrating OP AMP, then there must be two resistor, R input and R feedback.
I may be just having a dumb day, bit I would like to see a full circuit, with the components correctly defined before I could comment on the correctness of the value terminology used in the equation.
 
Quandry said:
...so I would read that the rectangular component is a resistor with a value of 1/S but I am not able to determine what 'S' signifies.
The 's' is the Laplace domain "frequency" variable/operator (yes, it's both). Reactive components such as inductors and capacitors have impedances in the Laplace domain of the forms:

Inductance L: sL
Capacitance C: 1/(sC)

Laplace transforms are a very handy way to write and solve differential equations using simple algebra.
 
It is a sad day when you don't learn something new:smile: Although vaguely aware of Laplace transformations I have never used them.
For a differentiating OP AMP I would use the formula Iinput = C x dVinput/dt
 
gneill said:
For the given component values it looks okay. Presumably the rectangular component is meant to represent a 1 F capacitor?

Yes! That's exactly what it was meant to be. Thank you
 
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