B Basic question - balance of forces....?

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The discussion focuses on calculating the forces exerted on a massless beam supported at two points with a weight applied at a specific distance. The user initially seeks help with a physics problem related to a trailer hitch, specifically how to determine the forces at each support when a 100 Newton force is applied. After clarifying the beam's length and weight placement, the user applies the principles of static equilibrium and torque to derive the forces at each support. The calculations show that one support exerts 80 lbs and the other 20 lbs. The user confirms their understanding and expresses gratitude for the assistance received.
tbaker
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I'm trying to find some basic physics information. Suppose you have a (massless) beam, supported at two points, 10 feet apart. You have a force (m*g) of 100 Newtons resting on that beam, say 4 meters from the left point (6 meters from the right)... How much force does that exert on each point, and how do you calculate it...? It seems this would be a simple physics example but I can't seem to find any info on an example like this. I'm working on a trailer hitch problem and the info would be useful...

Thanks.
 
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Sorry, I meant the beam is 10 meters long...
 
Try looking at the torque about each support, keeping in mind that the net torque about any point must be zero.
 
Thanks, but I was looking for a more specific 'example'. I'm not a student trying to get an answer for a homework problem... thanks anyway.
 
tbaker said:
Thanks, but I was looking for a more specific 'example'. I'm not a student trying to get an answer for a homework problem... thanks anyway.
That's not how we roll here. For spoon-fed answers you will need to look elsewhere. The expectation is that you will put in some effort, show your work and we will try to help when you get stuck.

So, can you pick a point on the beam and write down expressions for the torque about that point from each of the three forces on the beam?
 
So I think I've got it. It's been a while since I've done a physics problem.

So there's a beam (massless), 10 feet long. At each end is a support. A 100 pound weight is 2 feet from the left support (8 feet from the right). The system is in static equilibrium. Call the 100 pound weight F3. The left support F1, the right support F2. So F3 = F1 + F2. Using torque (I'll simplify it as FxD). So, since F1 and F2 are also in equilibrium with each other, F1*D1 = F2*D2, or F1*2 = F2*8.

So, F1 = 4*F2
So, F2 + 4F2 = 100
5F2 = 100
F2 = 20 lbs.
F1 = 80 lbs

Anyhow, I think I have what I need to get an idea what I'm trying to figure out.

Thanks.
 
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That looks correct.
 
Thanks pixel
 
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