Basis for Vector Space: Understanding the Exceptional Case

bphysics
Messages
33
Reaction score
0

Homework Statement



My notes has the following statement, but I seem to have forgotten to write down the conclusion of the statement before my professor erased it from the board.

"Any vector space V there will be a basis except for 1 type of space: "

Any ideas as to what that 1 type of space is?

Thanks
 
Physics news on Phys.org
perhaps "infinite dimensional"? They don't have a basis unless you assume the axiom of choice.
 
Probably the space consisting of just the 0 vector.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top