Stress Distribution in Bent Beams: Compression vs Tension

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In bent beams, the inner part experiences compression, leading to negative or minimum stress, while the outer part undergoes tension, resulting in positive or maximum stress. The bending stress is not calculated simply as force divided by area; it is influenced by the kinematics of deformation. The neutral axis of the beam is where the axial strain is zero, with positive strain on the outer side (tension) and negative strain on the inner side (compression). This relationship explains why the stress distribution is asymmetric, with maximum stress on the tension side and minimum stress on the compression side. Understanding these principles is crucial for analyzing beam behavior under bending loads.
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Homework Statement


I have the bent beam like this . The inner part of beam undergo compression , right , so it shortens. Why the stress is minimum at here ?
the outer part undergo tension , why the normal stress is maximum here ?
This is from my notes
http://imgur.com/a/H8fy4

Homework Equations

The Attempt at a Solution


since the outer part elongate , the surface area is max , so it should has min stress , right ? pressure = force / area [/B]
 
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chetzread said:

Homework Statement


I have the bent beam like this . The inner part of beam undergo compression , right , so it shortens. Why the stress is minimum at here ?
the outer part undergo tension , why the normal stress is maximum here ?
This is from my notes
http://imgur.com/a/H8fy4

Homework Equations

The Attempt at a Solution


since the outer part elongate , the surface area is max , so it should has min stress , right ? pressure = force / area [/B]
Bending stress is not equal to force / area.

The terms "minimum stress" and "maximum stress" are entirely relative in beam bending.
 
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SteamKing said:
Bending stress is not equal to force / area.

The terms "minimum stress" and "maximum stress" are entirely relative in beam bending.
can you explain why bending stress is min when the beam is compressed?
 
Analysis of the kinematics of deformation shows that on the outside of the bend (relative to the neutral axis), the axial strain is positive, and, on the inside of the bend (relative to the neutral axis), the axial strain is negative. At the neutral axis, the axial strain is zero. Along with these axial strains go axial stresses, which are proportional to the axial strains. So the axial stresses are positive on the outside of the bend (tension), and the axial stresses are negative on the inside of the bend (compression).
 
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Chestermiller said:
Analysis of the kinematics of deformation shows that on the outside of the bend (relative to the neutral axis), the axial strain is positive, and, on the inside of the bend (relative to the neutral axis), the axial strain is negative. At the neutral axis, the axial strain is zero. Along with these axial strains go axial stresses, which are proportional to the axial strains. So the axial stresses are positive on the outside of the bend (tension), and the axial stresses are negative on the inside of the bend (compression).
so compression correspnds to negative(minuimum stress) tension corresponds to positive(maximum stress) ??
 
chetzread said:
so compression correspnds to negative(minuimum stress) tension corresponds to positive(maximum stress) ??
Sure.
 
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