Beat frequency for hanging bar between two wires with added offset weight

AI Thread Summary
The discussion revolves around calculating the beat frequency produced by two wires supporting a bar with an offset weight. The fundamental frequency formula is applied, considering the tension in each wire due to the weight distribution. The calculated tensions for the wires are 221.25 N and 128.75 N, leading to a beat frequency of 28 Hz. There is clarification that beat frequencies can be perceived even at values greater than 15 Hz, contrary to a common misconception. The conversation highlights the relevance of beat frequencies in tuning musical instruments, emphasizing their auditory significance.
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Homework Statement


A uniform 165 N bar is supported horizontally by two identical wires A and B. A small 185 N cube of lead is placed 3/4 of the way from A to B. The wires are each o.75 m long and have a mass of 5.50 g. If both of them are simultaneously plucked at the center, what is the frequency of the beats that they will produce when vibrating in their fundamental?

Homework Equations


fundamental frequency = (1/2L) * √(F/μ).
where L is the length of the wire, (μ) is the mass per unit length, F is the tension in the wire
f(beat) = f1-f2.

The Attempt at a Solution


I tried to calculate the frequency of each wire A and B.
I let frequency1 be the frequency of the wire with the block closer to it, so wire B.

frequency1=(1/(2*0.75m))*√(F1)/(0.0055kg/0.75m)
frequency1=7.785*√F1

frequency2=7.785*√F2, as L and μ are the same for both wires.

This is where I got stuck. I tried to calculate the tensions:

F1= (1/2)*(165N) + (3/4)*185 = 221.25N
F2= (1/2)*(165N) + (1/4)*185 = 128.75N

I'm not sure if the tension due to the block would be distributed in the way I did.
When i put these tensions into the equation i get a large number, but i know that beats don't occur at frequency differences greater than 10-15 Hz.

Thank you.
 
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I have not checked your numerical answers all the way through but I do get the tension to be the same as yours.
I can't see anything wrong with your method.
I got the beat freq1uency to be 28Hz.
I will double check my numbers and correc this if it is wrong !
 
It is 28 Hz. I was a bit confused when i got this answer because my teacher said you don't hear beats at frequency differences greater than 15 Hz. Thanks for your help
 
Beat frequency is a frequency in its own right! It is the difference between the 2 frequencies and if that is an audio frequency you will hear it.
Do you play a musical instrument? Beat frequencies are used to tune instruments.
 
Sorry what i meant was you don't hear the individual beats and that it merges into dissonance or consonance. I should have just gone through with the 28 Hz. Thank you though, now i understand beat frequencies do occur at greater values. And no i don't play any instruments but my prof demonstrated tuning a guitar.
 
I know what you mean... low beat frequencies sound like a 'throb' rather than a 'note'
Your prof probably got to produce slow throbs as he tuned his guitar!
But the beat frequency can sound (is!) a genuine note in its own right.
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