Belt Drive Pulley: Mean Diameter 300mm, Angle 180°, 920 RPM

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The discussion centers on a belt drive pulley with a mean diameter of 300mm, an angle of contact of 180°, and a rotation speed of 920 RPM. The smaller belt tension is given as 50 N, with a coefficient of friction of 0.3, while centrifugal effects are neglected. The user attempts to calculate the velocity using the formula V=piND but becomes confused due to missing forces F1 and F2. There is a request for assistance in solving the problem, indicating a need for clarification on the calculations or additional information. The conversation highlights the challenges faced in mechanical engineering calculations involving belt drive systems.
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Homework Statement


A belt drive pulley has a mean diameter of 300mm, an angle of contact of 180° and rotates at 920 rpm. Smaller belt tension is 50 N and coefficient of friction is 0.3 Neglect centrifugal


Homework Equations


V=piND


The Attempt at a Solution


pi*(920/60)*0.3=14.45 ms


after that in sort of lost because question doesn't give F1 or F2


please help thanks
 
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findinganswer said:
A belt drive pulley has a mean diameter of 300mm, an angle of contact of 180° and rotates at 920 rpm. Smaller belt tension is 50 N and coefficient of friction is 0.3 Neglect centrifugal

Hi findinganswer. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Is there a question to accompany the above information? https://www.physicsforums.com/images/icons/icon5.gif
 
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