Calculating Bending Moments for a Round Bar: E=200x103 N/mm2, D=125mm

  • Thread starter Thread starter Confusedbiomedeng
  • Start date Start date
  • Tags Tags
    Bending Moments
AI Thread Summary
The discussion focuses on calculating the maximum allowable bending moment and the radius of curvature for a round bar with a diameter of 125mm and Young's modulus of 200x10^3 N/mm². The calculations for the bending moment yield a result of approximately 3,355,582.72 Nmm, while the radius of curvature is calculated to be 1.4mm. Participants emphasize the importance of including units in calculations for clarity and accuracy. There is some confusion regarding the equations used, particularly whether to use M/I = E/R or an alternative formula for the radius of curvature. Overall, the thread highlights the need for clear communication and correct application of formulas in engineering calculations.
Confusedbiomedeng

Homework Statement


a round bar,125mm in diameter , is to be used as a beam. if youngs modulus for the material E=200x103 N/mm2
Calculate:
i)Maximum allowable bending moment(12marks)
ii)The radius of curvature at the point of maximum bending moment(8marks)

Homework Equations


σ/y=m/I=E/R
I=πD4/64[/B]
y=125/2

The Attempt at a Solution


i)17.5/62.5=M/11984224
0.28x11984224=3355582.72Nmm=M
ii)0.28/200x103=1.4mm=R

Can anyone tell me where I am going wrong ?
 
Physics news on Phys.org
Confusedbiomedeng said:

Homework Equations


σ/y=m/I=E/R
I=πD4/64[/B]
y=125/2

The Attempt at a Solution


i)17.5/62.5=M/11984224
0.28x11984224=3355582.72Nmm=M
ii)0.28/200x103=1.4mm=R

Can anyone tell me where I am going wrong ?
Can you put some units onto your workings out? It would be easier to follow what you are doing (for us and for you).
 
scottdave said:
Can you put some units onto your workings out? It would be easier to follow what you are doing (for us and for you).
in the final answers i have them put in ?? should i put them in throughout the workings??
 
Confusedbiomedeng said:
in the final answers i have them put in ?? should i put them in throughout the workings??
It would help me to figure out what you were doing.
 
You left out the tensile strength in the problem statement.
 
  • Like
Likes scottdave
Confusedbiomedeng said:
y=125/2

The Attempt at a Solution


i)17.5/62.5=M/11984224
0.28x11984224=3355582.72Nmm=M
ii)0.28/200x103=1.4mm=R

Can anyone tell me where I am going wrong ?
So where did the 17.5 come from? I am guessing it is σ. It would be nice to eliminate guessing, when figuring out where you are going wrong.
 
scottdave said:
So where did the 17.5 come from? I am guessing it is σ. It would be nice to eliminate guessing, when figuring out where you are going wrong.
Yes it is stated in the question and I forgot to put it in so 17.5n/mm2 then y is 125/2 because everything is in mm2 so I don't need to change the diameter . I ,I worked out by ∏(1254)/64 but now I'm wondering should the equation for I be ∏(D4)/32?? So sorry for any confusion
 
I confirm you calculation of the bending moment, and I confirm the factor of 64 in the denominator. But the equation for the radius of curvature should be $$R=\frac{Er}{\sigma}$$where r is the radius of the bar.
 
  • Like
Likes scottdave
Chestermiller said:
I confirm you calculation of the bending moment, and I confirm the factor of 64 in the denominator. But the equation for the radius of curvature should be $$R=\frac{Er}{\sigma}$$where r is the radius of the bar.
Ok could you just explain why that equation and not M/I =E/R? And so I have the right answer for the allowable bending moment
 
  • #10
Confusedbiomedeng said:
Ok could you just explain why that equation and not M/I =E/R?
It's that too. I just found it easier to calculate it the other way.
 
Back
Top