Beta Decay of He3 Atom: Electron Emission vs. Shell Occupancy

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Beta decay of the He3 atom results in the emission of an electron and an antineutrino, leaving the atom with only one electron. The emitted beta decay electron possesses significantly higher energy, allowing it to escape rather than occupy the lowest electron shell. The energy released during this decay is in the keV range, while the binding energy of electrons is in the eV range, highlighting the energy difference between nuclear and chemical reactions. This process demonstrates how nuclear decay can influence atomic structure and electron configuration. Ultimately, the dynamics of energy levels dictate the behavior of the electrons post-decay.
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Does this decay leave the He3 atom with only one electron? The only decay productsas far as I can tell are the electron and antineutrino, so it seems like the atom would only retain the original H3 electron.

Now if that's the case, why is the beta decay electron emitted rather than fitting into the lowest electron shell?
 
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I don't have the specific numbers. However I believe the decay electron is emitted with a lot more energy and therefore escapes. The He3 nucleus picks up a swtray electron.
 
Correct. Energy released in the process is in the keV ranges. Binding energy for electron is going to be in the eV ranges.
 
So essentially it's the difference in energy between chemical and nuclear reactions?
 
In short, yes.
 
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