Bicycle Forces in Circular Motion

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A bicyclist traveling in a circle with a radius of 22.5 m at a speed of 8.62 m/s has a mass of 79 kg. The force of friction calculated using the formula F=mv^2/R is 260.9 N. To determine the net force on the bicycle, one must consider both the force applied by the biker and the force of friction, which acts in the opposite direction. The vertical forces on the bike cancel out, suggesting that the net force could be equal to the force of friction. Understanding these forces is crucial for analyzing circular motion dynamics.
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Homework Statement



A bicyclist travels in a circle of radius 22.5 m at a constant speed of 8.62 m/s. The bicycle-rider mass is 79 kg. Calculate the magnitudes of (a) the force of friction on the bicycle from the road and (b) the net force on the bicycle from the road.

Homework Equations


a. F=mv^2/R
Fnet=ma

The Attempt at a Solution


i got a. to be 260.9N by using F=mv^2/R
for b, i have no idea. Could they be the same since the vertical forces on the bike cancel out?
 
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to answer b, you need to find the force applied by the biker (f=ma) then to get fnet you need to add the force applied + the force of friction. but keep in mind that the force of friction would be negative since it is going the opposite direction :)
 
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