Bohr Model of the Hydrogen atom: Prove that Eo = 13.6 eV

AI Thread Summary
The discussion focuses on verifying the ground state energy equation of the Bohr model for the hydrogen atom, specifically simplifying it to Eo = 13.6 eV. Participants identify errors in the constants used, such as the mass of the electron and the correct constant for Coulomb's Law. They emphasize the importance of careful arithmetic and using scientific notation to avoid rounding errors. Additionally, there is clarification on the distinction between charge (e) and energy (eV), stressing that energy must be converted from Joules to electronvolts. The conversation concludes with appreciation for the guidance received in resolving the misunderstandings.
TRE
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Homework Statement



Verify that the equation of the ground state energy Eo of the Bohr atom: Eo= (2pi2e4mek2)/h2
simplifies to Eo = 13.6 eV. Show clearly how the units of the different
quantities in the equation simplify to the eV.

This is all they give. Nothing more.



Homework Equations




Eo= (2pi2e4mek2)/h2



The Attempt at a Solution



me = 9.10938291 x 10-19 Kg

k = 1.3806488 x 10-23J/K

h = 6.62606957 x 10-34J.s

1.6 x 10-19J = 1 eV

2 pi2 = 19.7392088


e4 = 6.589333674 x 10-76 C4

k2 = 1.906195527 x 10-46J2/K2

h2 = 4.390478986 x 10-67J2.s2

when you multiply the above constants together : 2pi2.e4.me.k2 = 0 which means that the whole equation is equal to zero thus Eo = 0 and clearly Eo is not equal to 0 but to 13.6 eV

Also for the units I obtain for the answer when I multiply together and then divide is (C4.Kg/(K2.s2) which is not correct and I did not see any other units for the constants we have to use.
 
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when you multiply the above constants together : 2pi2.e4.me.k2 = 0
Does that make sense mathematically:
How can you multiply a lot of non-zero numbers together and get zero?

Perhaps your calculator has rounded off?
How should you go about multiplying very small numbers - hint: exploit the scientific notation.
 
Sorry you feel that way ... and yes, I have done this myself. Many times.

You have clearly made a mistake in the arithmetic since it is not possible to multiply a bunch of non-zero numbers together and get zero for the answer. If it is not a matter of your calculator deciding that 10^-70 or whatever is zero, then it is something else.

GO through the calculation carefully and see which step gets you the zero.

Note: if the dimensions do not match, then the equation is wrong.
 
TRE said:

Homework Statement



Verify that the equation of the ground state energy Eo of the Bohr atom: Eo= (2pi2e4mek2)/h2
simplifies to Eo = 13.6 eV. Show clearly how the units of the different
quantities in the equation simplify to the eV.


Homework Equations




Eo= (2pi2e4mek2)/h2



The Attempt at a Solution



me = 9.10938291 x 10-19 Kg
there is a mistake here: me = 9.10938291 x 10-31kg.

TRE said:
[STRIKE]k = 1.3806488 x 10-23J/K[/STRIKE]

That 'k' is not the Boltzmann constant, but the constant ke in Coulomb's Law: ke=8.9875 Nm2C-2 .

TRE said:
h = 6.62606957 x 10-34J.s

e=1.6 x 10-19[STRIKE]J = 1 eV[/STRIKE]
You can not replace e with 1 eV. eV is energy, e is charge. e=1.6 x 10-19 C and 1 eV= 1.6 x 10-19 J.

When you multiply the constants, you get the energy in Joules. You have to convert it to eV-s by dividing it 1.6x 10-19 J/eV

Do not forget to set your calculator to SCI mode, to use the normal form of numbers.

ehild
 
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To ehild

Thank You very much for your help, I appreciate it. I finally understand where I went wrong.

Regards
 
You are welcome.

Just a hint: when you have to calculate with very big or very small numbers, treat the exponents separately, add and subtract them.

ehild
 
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