Box Acceleration and Velocity: Solving for Vertical Motion

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The problem involves a 5.0 kg box being pulled upwards with a force of 68 N. The acceleration of the box is calculated using the formula a = T/m - g, resulting in an acceleration of 3.8 m/s². After 2 seconds, the vertical velocity of the box is determined to be 7.6 m/s using the equation v = vo + axt. The calculations are confirmed to be correct. This demonstrates the application of Newton's second law and kinematic equations in solving vertical motion problems.
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Homework Statement


A box of mass 5.0 kg is pulled vertically upwards by a force of 68 N applied to a rope attached to the box. Find a) the acceleration of the box and b) the vertical velocity of the box after 2 seconds.

Homework Equations


ma = Force and a = T/m -g
a = 68/5 - 9.8 = 3.8 m/s^2

v = vo + axt
v = 0 + 3.8 x 2 = 7.6 m/s.

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