Brake Rotor Heat: Calculating Temperature for 120kg Object at 30mph

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    Brake Heat Rotor
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To calculate the heat generated by a brake rotor when stopping a 120kg object traveling at 30 mph, the kinetic energy is determined to be 11,760 Joules. The material of the rotor is crucial for understanding how much energy is needed to raise its temperature. Factors such as airflow, turbulence, ambient temperature, and humidity also significantly affect heat dissipation. Advanced simulation software like SolidWorks can model these variables, though it can be prohibitively expensive. Practical testing is suggested as a viable alternative, with recommendations for increasing surface area through design modifications.
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This isn't so much a homework question but rather something I need to know in order to design something.
I need to know how much a brake rotor will heat up during braking. The force it needs to stop is a 120kg object traveling at 30 mph. I don't know any of the equations necessary to figure this out. I need to know this because I am designing a brake rotor for a bike and it cannot exceed a certain temperature. Any help would be great. Thanks.
 
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E(kin) = ½*m*v*v

m=120kg
v=14m/s (30mph)

E(kin)=11760Jouel

You need to know which material you are using. For the given material you can find how much energy you need to heat one kilogram one degree celcius (or which ever scale you crazy americans use) ;-)
 
How would I deal with heat dissipation?
 
I would think you would have to know the exact airflow and turbulance around the break, the air temp. and the air hum. You would need a big computer progran such as SolidWorks to simulate it! With a price tag of around 10.000dollers fore a single user program, it might be a little much! I think Ferrie spends millions on these calculations and simulations.
I would propose testing it! The larger the surface arrea the better (drill a lot of holes) :-)
 
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