C. What is the average energy released per fission event in this chain reaction?

[pooka]

The fission reaction n + 235U → 236U* → 141Ba + 92Kr + 3n produced 170 MeV of kinetic
energy.

A. How many of these fission events are needed to produce energy of 1 kilowatt- hour (kWh), that is, the energy it takes to run your blow dryer for an hour?

B. How many neutrons are produced in this chain reaction process?

I know how to do A. I was just wondering how to do part B. Is it just: 3^(# of reactions needed)?

 

[CompuChip]

Why do you want to exponentiate that?
And are you sure that in the end, you have 3 neutrons left for each reaction?

 

[dynamicsolo]

For part B, you need to give the net change in the number of free neutrons.

 

[CompuChip]

If you don't see why it shouldn't be 3, take a look at dynamicsolo's signature

 

[chukie]

Thanks guys!