Calculate mass from acceleration and radius

AI Thread Summary
To calculate the mass of an object using the acceleration due to gravity and radius, the equation F = GM/r^2 is essential, where G is the gravitational constant. The user initially misapplied the formula but was guided to correctly derive the mass using M = F/a. The discussion clarified that gravitational acceleration is independent of mass and emphasized the importance of understanding the relationship between acceleration, gravitational force, and mass. The scenario involved calculating the mass of an imaginary planet with a radius of 12 m and an acceleration of 2 m/s^2. The conversation concluded with advice to work symbolically before substituting numerical values to ensure dimensional accuracy.
kmh36
Messages
3
Reaction score
0

Homework Statement


How do you calculate the mass of an object just from the acceleration from gravity and the radius?

Homework Equations


My thoughts were F=GM/r2, then once you find F, you can calculate mass by M=F/A
G= 6.67 x 10^11
r = 12
Acceleration = 2 m/s^2

The Attempt at a Solution


(6.67 x 10 ^-11) / 12^2 = 4.63 * 10 ^-13
M = (4.63 * 10 ^-13)/(2 m/s^2) = 2.31 ^-13 kg
 
Physics news on Phys.org
Hello 10 m/s, and welcome to PF :smile:

Acceleration from gravity due to another object happens to be independent of mass. You are missing an m in your ##F = {G Mm\over r^2}## that, with ## F= ma## goes over in ##a = {G M\over r^2}##.

[edit] compare gravitational acceleration at the surface of the earth:
G = 6.67E-11 N/(m/kg)2
M = 5.97E+24 kg
r = 6.37E+06 m
g = GM/r2 = 9.82E+00 m/s2
 
Last edited:
I'm sorry, I still don't understand! What is 10 m/s?
I didn't think my equations were right, but I really don't know what to try next. I don't know the mass which is really hanging me up.
 
10 m/s is 36 km/h, just a corny attempt at humor.

You don't know the mass in what kind of situation ? Could you be a bit more elaborate in the problem statement ?

Apparently you have two "things", 12 m apart, and "something" accelerates with 2 m/s2 ?
 
Ha, that is funny!

I'm trying to calculate the mass of an imaginary planet. All I have given to me is the radius (12m) and the acceleration due to gravity on that surface (which is 2 m/s2)
 
Well, then you're in business! So the problem statement is:

What is the mass of a planet with radius 12 m (!?), given that the acceleration due to gravity on the surface of that planet is 2 m/s2.

And you have the equation. Is it clear that GM/r2 is not a force but an acceleration ?

It's a very dense planet. Just for the fun of it, calculate the density in kg/m2 assuming its a sphere...

tip: work in symbols (a, G, M, r) as long as you can, until you have a final expression (a = ...) . Then check dimensions and then fill in numbers.
 
  • Like
Likes MacLaddy
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top