Calculate phase between sine waves given the time difference

AI Thread Summary
To calculate the phase difference between sine waves given a time difference, the formula used is time difference multiplied by 2πf, where f is the frequency. In this case, the frequency is derived from the equation 3cos(30t - π/2), resulting in a frequency of 30. The calculated phase difference was -1.5 radians or approximately -85.94 degrees, while MATLAB provided a slightly different value of -76.3995 degrees. The discrepancy is attributed to rounding errors, particularly since the time difference of 0.05 seconds has only one significant figure. Accurate calculations should consider significant figures to improve precision in results.
exidez
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Homework Statement



How do i find the phase between sine waves knowing the time difference between each?
http://users.bigpond.net.au/exidez/sinewave.jpg

Equation for the main function is 3cos(30t - Pi/2)
The smaller sine wave is of the same frequency when is settles in a steady state.


Homework Equations



i thought it was
time difference * 2*Pi*f = phase difference in radians

The Attempt at a Solution


30 = 2*Pi * f

-.05*30 = 1.5 radians
-1.5*360/(2Pi) = -85.94 degrees

MATLAB give the phase difference as -76.3995 degrees
this is equivalent to -0.0444474274 difference in seconds

Is this just due to rounding error??
 
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i think i just answered my own question... 2.57 seconds for the larger sine wave still give an amplitude of 3.. In this case the time difference is -0.04.

it definitely is due to rounding
 
exidez said:

Homework Statement



How do i find the phase between sine waves knowing the time difference between each?
<image not shown>

Equation for the main function is 3cos(30t - Pi/2)
The smaller sine wave is of the same frequency when is settles in a steady state.

Homework Equations



i thought it was
time difference * 2*Pi*f = phase difference in radians

The Attempt at a Solution


30 = 2*Pi * f

-.05*30 = 1.5 radians
-1.5*360/(2Pi) = -85.94 degrees

MATLAB give the phase difference as -76.3995 degrees
this is equivalent to -0.0444474274 difference in seconds

Is this just due to rounding error??

You did it right, but note that the 0.05s time difference contains just one significant figure.
 
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