"Calculate Resultant Force on Vertical Dam Wall

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To calculate the resultant force on a vertical dam wall, the pressure varies with depth, necessitating integration for an accurate solution. The initial approach used a uniform pressure assumption, which is incorrect due to the changing pressure with depth. The correct method involves integrating the pressure equation from the surface to the height H of the water. This results in the pressure at the base being expressed as P = PaH + (pgH^2)/2. The final force on the dam wall is then calculated as F = HW(PaH + (pgH^2)/2).
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Homework Statement


Pressure_2.jpg: http://www.imageupload.org/thumb/thumb_8609.jpg
A vertical dam wall has a width w. Water is filled to a height H behind the dam. Calculate the resultant force on the dam wall.



Homework Equations


P=F/A
P= Pa + p*g*h





The Attempt at a Solution


Using picture to solve the question
P=F/A
A=H*W
Thus P=Pa g*h*p where p is density and P is pressure.
Thus F=P*A=H*W*(Pa + gHp) where g is gravity.

Is this correct?
 
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Your solution, as I've understood it, would work if the pressure were uniform, that is, constant. However, it changes as you go down, so you would need to perform an integration to determine the net force.
 
Metaleer said:
Your solution, as I've understood it, would work if the pressure were uniform, that is, constant. However, it changes as you go down, so you would need to perform an integration to determine the net force.

Aha, I see. This is first fluid question I had involving integration.
Thus, I integrated \intPo + pgh dh from 0 to H.
Getting P=PaH + pgH^2/2.
Thus
PA = HW(PaH + pgH^2/2).
Better now?
 
anyone?
 
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