Calculate Stress & Strain of Marble Column - 1.5m^2, 2.5x10^4kg

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SUMMARY

The discussion centers on calculating the stress and strain of a marble column with a cross-sectional area of 1.5 m² supporting a mass of 25,000 kg. The stress is calculated using the formula (mass x gravitational acceleration) / area, resulting in a stress of approximately 163,333.33 Pa. However, the strain cannot be determined without additional information such as the column's original length or Young's modulus, which are essential for calculating strain using the formulas delta Y/original length or strain/Young's modulus.

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  • Research Young's modulus for marble to understand its mechanical properties
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A marble column of cross-sectional area 1.5 m^2 supports a mass of 2.5×10^4 kg.



What is the stress within the column?
What is the strain?

I have already found the stress in the column by taking (25000kgx9.8 m/s^2)/1.5m^2
The problem is i have no clue how to find the strain given this information. I know strain is delta Y/ original length, or strain/youngs modulus.
 
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Without any information regarding its length or Young's modulus, you can't find the strain.
 
This was all that was given to me in the problem...does anyone have any clue.
 

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